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Discussion Starter #1 (Edited)
Been exploring drop options. I have compiled a list of data for springs and drops. Thought it would be helpful if I shared, please fill in the blanks or add springs, or correct bad data. spring weights are in lbs/inch

OEM
03-06 EX/LX
07-up EX/LX ?
07-up SC .9" drop (used the height values on the honda website and subtracted not sure how much of that is actually spring height though)

Eibach
03-06 (1.7" F/R)
07-up SC (1.0"/1.5" F/R)
07-up EX (1.5"/2.0" F/R)
All years...140/300F, 240/720R

Tein stech
2wd (2.6"/2.13" F/R)
4wd (2.52"/2.44" F/R)
03-06.......300F, 620R

H&R (1.5"/1.4" F/R)
03-06.....280F, 495R

Skunk 2 (1.5"/1.4" F/R)
03-06.....134/253F, 320-574R

Megan Racing
03-06 (1.5" F/R)
235F/210R
07-up (no info given on website but springs offered, assuming same spring weights)

Tein Basic Coilovers
Adjustable height
Constant Damping
390F/670R

KSPORT
Adjustable height
Adjustable Damping
560F/728R, optional 843R
 

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For the KSports, you might want to add the optional 15K spring rate.
Im not sure how to convert kg/mm to lbs/in. I did see in one post that
someone said it was 840. KSport does list a 14.8 spring and translates
that to 829. So 840 doesnt sound wrong. This is for the rear springs of course.
 

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Discussion Starter #3
cool, added it in. Anyone got the inside scoop with honda and can get OEM rates?
 

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If I remember correctly, when I got the specs on ksport springs after the initial run, the guy said they tested out at 890, hope that helps.
 

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For the KSports, you might want to add the optional 15K spring rate.
Im not sure how to convert kg/mm to lbs/in. I did see in one post that
someone said it was 840. KSport does list a 14.8 spring and translates
that to 829. So 840 doesnt sound wrong. This is for the rear springs of course.
since there are 2.2 lbs/kg and 25.4mm/in, to convert kg/mm to lbs/in just multiply the kg/mm number by (2.2/25.4= 0.0866).
so 15k kg/mm becomes ~1300 lbs/in.
 

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since there are 2.2 lbs/kg and 25.4mm/in, to convert kg/mm to lbs/in just multiply the kg/mm number by (2.2/25.4= 0.0866).
so 15k kg/mm becomes ~1300 lbs/in.
Your math is all wrong!! We know from the Ksport website that
10K kg/mm = 560 lbs/in
13K kg/mm = 728 lbs/in
14.8K kg/mm = 829 lbs/in

So how do you get 15K kg/mm = 1300 lbs/in????
You are saying that .2K kg/mm difference = 471 lb/in difference!!!

I think the flaw was in your equation. You are dividing lbs by mm.
You formula should be .454 kg/lb and 25.4mm/in and you get .454/25.4=.017874

So with this formula you get
10/.017874 = 559.472 or 559lbs/in
13/.017874 = 727.313 or 727lbs/in
14.8/.017874 = 828.018 or 828 lbs/in
So with that looking closer to what we know, I get
15/.017874 = 839.208 or 839 lbs/in which is MUCH closer to the 843 that
snowdreams posted and even closer to the 840 that I posted.

And if what insane says is correct, then the rear optional springs would be 15.9K
15.9/.017874 = 889.560 or 890 lbs/in.

Correct me if I am wrong.
 

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Discussion Starter #8
I just used my calculator to convert. call me lazy. Can't edit it anymore but a few lbs ain't going to make a huge difference. Still hoping someone chimes in with how to get the OEM info.
 

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I just used my calculator to convert. call me lazy. Can't edit it anymore but a few lbs ain't going to make a huge difference. Still hoping someone chimes in with how to get the OEM info.
It will be near impossible to get the OEM rates. Honda wont release them.
I bet if you call all the companies that you listed above, NONE of them will
be able to tell you either. They will just say that theirs are 10 - 20% stiffer.
But they will be guessing. I could be wrong.

I also noticed that you didnt have the optional rear spring rate for the Teins.
I dont know what it is, I know they have one, its here on the forum somewhere.
 

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Discussion Starter #10
I all ready did call most of them. No one had much info, especially OEM info. And they really often didn't want to give up their own rates.
 

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Here are my crappy on element measurements plugged into the spring rate database: Feel free to do a better job when you have your springs off of the car:

Front: .605" stock dia, 7" coil dia, 3 active coils: 245.5lbs/in
Rear: .605" stock dia, 4.75" coil dia, 3.5 active coils: 772.5 lbs/in

Just for reference, if i'm off in the back by +0.5" then the rate is 549lbs/in instead of 772.5. If I'm off in the front by -0.5" then the rate is 313lbs/in

So.... take this with a grain of salt.

I did manage to get the calipers around the rear springs, so I'm confident of the stock diameter and the coil diameter... fronts, only confident on the coil diameter
 

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I'm going into an AutoZone today to measure quickstruts for a project and want to drop some maths here for the benefit of feedback and to save someone else from effort duplication if at all possible:

My EX/4WD weighs 3641lbs with a 57/43 weight ratio (according to Honda) and the rear lift geometry is a 1.5 to 3.5 lift ratio (sparman lift thread) giving us a .42 ratio of lift... (1.5/3.5)

Lets say each wheel, shock, brake and whatnot weights ~125lbs (they aren't supported by the suspension) and we've got a total spring load of 3141lbs

IF (and I'll be able to verify by measuring the springs) my guessed spring rates above are correct, then:

491lbs/in front between the two shocks to carry 1825lbs and preloads the spring 3.75" dropping the car 3.75" from completely unloaded suspension.

649lbs/in rear. carries 1316lbs and preloads the spring 0.85" dropping the rear of the car 2" from completely unloaded suspension.


The engineering assumptions I'm making are many (and listed above) and the impact of minor errors in measurement could result in fairly inaccurate calculations. If you want to use the above, I'd suggest you prepare for those inaccuracies or test them (i'd put weight between the struts and measure the spring compression. weighing 200lbs makes me a good candidate for the weight, but I don't have a buddy handy right now to measure.)
 

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Nope, here is what a proper dimensional analysis looks like:

The given factor is displayed as a fraction & each conversion factor similarly displayed as fractions & multiplied side by side to allow for the cancellation of the terms that you want to eliminate. The common units cancel across the 3 fractions, in this case mm & kg. Then you simply multiply the surviving terms across the numerator & denominator. You orient the conversion factors so that they will conveniently cancel across the fraction bar (vinculum).

15 kg/mm x 2.205 lbs/kg x 25.4 mm/in = (15)(2.205 lbs)(25.4) = 840.105 lbs/in

Note that the mm & kg canceled above & below the fraction bar. I would use strike through but it is not available on this forum's format. There are only the concerns with significant figures left but this will work every time without fail guys.
 
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